extension tube formulas
/forum/topic/630213/0

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rdjphoto
Registered: Jun 02, 2005
Total Posts: 36
Country: Canada

I know I read this somewhere here before, but I was wanting to know the formulas regarding using extension tubes.

For example for a given lens adding an extension tube of 25mm how do you calculate how much closer can you focus.

Also how would you calculate your magnification factor eg. how close do we get to true macro 1:1

Thanks



Rampai65
Registered: Jun 04, 2003
Total Posts: 879
Country: United States

For a lens set at infinity you would need focal length equivalent of extension to make it give you 1:1. That means a 50mm Lens would need 50mm of extension at Infinity focus to achieve 1:1 magnification. This formula also comes with some other caveats, like the lens has to be symmetric and all that I believe.

Best thing is to shoot a scale at the MFD and see whats the max magnification you can get.



Rainer
Registered: May 18, 2004
Total Posts: 494
Country: United States

You will need the thin lens formula, which is

1/o + 1/i = 1/f

where o and i are object and image distance, respectively, and f is the focal length. As an example, let's look at the 50 f/1.8. The closest focusing distance of this lens is 0.45 m = 450mm. We now get the image distance from

1/450mm + 1/i = 1/50mm,

i = 56.25mm. The magnification factor is i / o = 56.25mm / 450mm = 0.125. Now add the extension tube. i' = i + 25mm = 81.25mm. We find o' from

1/o' + 1/81.25mm = 1/50mm,

o' = 130mm, the new closest focusing distance. And the new magnification factor is i'/o' = 81.25mm / 130mm = 0.625.

The slight differences from the magnification factors given in Canon's Lens Works are due to these lenses being not exactly "thin" lenses.

Rainer



rdjphoto
Registered: Jun 02, 2005
Total Posts: 36
Country: Canada

My math fails me

How did you arrive at i=56.25 ?



Rainer
Registered: May 18, 2004
Total Posts: 494
Country: United States

rdjphoto wrote:
My math fails me

How did you arrive at i=56.25 ?


Let's do it step by step (ignoring the "mm"):

1/450 + 1/i = 1/50

0.002222 + 1/i = 0.02

1/i = 0.02 - 0.002222 = 0.017778

i = 1 / 0.017778 = 56.25

I hope this helps,

Rainer



rdjphoto
Registered: Jun 02, 2005
Total Posts: 36
Country: Canada

Thanks,

Right after I posted the message I figured it out



Pixel Perfect
Registered: Aug 16, 2004
Total Posts: 7279
Country: Australia

If you don't need to know the new MFD, then the extra magnifcation m' the tubes gives is simply

m' = ext/FL = 25/50 = 0.5

which is added to the inherent magnification of the 50mm, so

m" = m' + 0.125 = 0.625.



Dan Lai
Registered: Dec 15, 2007
Total Posts: 105
Country: United States

What is MFD?



Rainer
Registered: May 18, 2004
Total Posts: 494
Country: United States

Dan Lai wrote:
What is MFD?


MFD = minimal focus distance



Duncan Gibson
Registered: Aug 25, 2007
Total Posts: 430
Country: Canada

Minimum Focusing Distance



Dan Lai
Registered: Dec 15, 2007
Total Posts: 105
Country: United States

Thanks Rainer and Duncan



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