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| Re: silly inverse square law question. |
curious80 wrote: because the total light hitting the lens is now less and that is why the brightness and exposure remains identical
Man you have to read the whole thing. The total light reaching the lens from that subject is less, but that light is now spread over a smaller section of the sensor. So the light intensity on the sensor remains the same and thus the total exposure remains the same. There - I have now said the same thing around 5 times in 5 different ways Please refer to my white square in the black wall example above, and tell me what problem do you find in that description?