jasin Offline Upload & Sell: Off
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CW did you get your FACTS from the back of a pack of honey smacks or what?
I think I will leave it to you guys to work out , oh and nsbca don't you mean F5?
Cheers,
Jasin.
Oh and CW sorry I lean to the right but try this on for size!
Why smaller image sensors have greater DOF
1. For a given field of view (picture angle), the lens focal length must be proportional to the diagonal of the image sensor. For example, the diagonal of 35 mm film is 43 mm. A lens with focal of 43 mm, mounted in a 35 mm film camera, will provide a field of view of 53º. To obtain the same field of view (53º) in a sensor witch diagonal is half that of 35 mm film, we must use a lens witch focal length is 43/2 mm. (By the way, a lens with focal length that is equal to the diagonal of the sensor is called a “normal lens”, as it provides a field of view that is approximately the same as the human eye).
2. In the formula of the hyperfocal distance, the diameter of COC must be proportional to the size of the image sensor. The reason for this is obvious: the image from a smaller sensor must be more enlarged than an image from a larger sensor. So, in order to obtain the same COC in the printed image, the COC (in the sensor image) must be smaller for the smaller sensor.
From what was told in the previous paragraphs, it can be demonstrated that, for a given lens aperture and a given field of view, the hyperfocal distance is directly proportional to the sensor size (that is, a smaller sensor has smaller hyperfocal distance and, as a consequence, larger DOF). I leave the demonstration of this statement as an exercise to the reader.
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