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Come down pls, a gravity force use newton unit and if it in static state this force= the mass (kg)x10
means the earth pull this mass with certaint force.I corrected typos by adding 2 periods above.If this mass is on moving hands the G.force is more than that because of another E=mc 2, and who knows the exact formula is.That formula you gave used to define force of a free fall mass hit the ground, and evalute this force could break the camera or not, so not that force pull down the hands.OK?not big deal here.
No, you are wrong, but it is irrelevant to the Zeiss conversation though.
I'll reply because you are speaking a flawed argument. I'm sorry to the other people as this is not relevant to the Zeiss conversation..
F = (m x a) = (m x g) (in case the subject is within the earth's gravitational field, which it is)
All subjects, whether free falling or static are subject to (F = m x g) as long as they are within the potential field of gravity . For this not to hold true, the object would have to be millions of miles away from Earth. This force acts upon the subject irregardless if the object is falling or at rest. If the objects exists on earth and it has mass, then such force acts upon it. If it weren't like that, then objects at rest could fly all of the sudden.
In addition to a graviational force, there can be additional forces acting upon a body. That happens when a body is subject to an acceleration, say a car, train or just running with your Zeiss to take a pic. When an additional force acts upon, there is a simple vectorial addition of such forces. What you refer to as G force is just the simple act of applying a secondary, additive force upon your object by means of acceleration.
E = m x c^2 refers to energy, which is not an additive quantity to force. It's irrelevant.
No big deal here either. No need to spread flawed knowledge though..